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24.maximumOfAllSubarrays.cpp
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24.maximumOfAllSubarrays.cpp
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#include<bits/stdc++.h>
#include<unordered_set>
using namespace std;
typedef vector <int> vi;
typedef pair< int ,int > pii;
#define endl "\n"
#define sd(val) scanf("%d",&val)
#define ss(val) scanf("%s",&val)
#define sl(val) scanf("%lld",&val)
#define debug(val) printf("check%d\n",val)
#define all(v) v.begin(),v.end()
#define PB push_back
#define MP make_pair
#define FF first
#define SS second
#define ll long long
#define MOD 1000000007
#define clr(val) memset(val,0,sizeof(val))
#define what_is(x) cerr << #x << " is " << x << endl;
#define printValue(x) cout << x << " ";
#define OJ \
freopen("input.txt", "r", stdin); \
freopen("output.txt", "w", stdout);
#define FIO ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
// Add new elements at the back, and keep only largest one and remove all the smaller ones
// the front element will ALWAYS be the largest cause
// it reached front by removing all weaker ones
// add front in each window/loop
vector<int> maximumOfAllSubarray(vector<int>& arr,int k) {
deque<int> queue;
vector<int> ans;
int i = 0;
int size = arr.size();
// traversing K elements for filling the queue
for(; i < k; i++) {
// remove the weaklings
while((!queue.empty()) && arr[i] >=(arr[queue.back()])) {
queue.pop_back();
}
queue.push_back(i);
}
for(; i < size; i++) {
// add the MAX to ans
ans.push_back(arr[queue.front()]);
// Remove out of window elements from front as they might be max but expired
while((!queue.empty()) && queue.front() <= i - k) {
queue.pop_front();
}
// Remove the weaklings even equal ones because latest is better
while((!queue.empty()) && (arr[i] >= arr[queue.back()])) {
queue.pop_back();
}
queue.push_back(i);
}
ans.push_back(arr[queue.front()]);
return ans;
}
int main() {
FIO
OJ
int size;
cin >> size;
vector<int> arr(size);
for(auto &it : arr) {
cin >> it;
}
int k;
cin >> k;
vector<int> ans = maximumOfAllSubarray(arr, k);
for(int i : ans) {
debug(i);
}
return 0;
}