oiio:subimagename

[20percentgrey]

When looking at an exr file from Python, the names are always subimage0, subimage1,...
Trying to use the attributes like the oiiotool examples suggest (oiio:subimagename), appears not to work. Is this the correct way to set the subimage name? Tried both attributes below as mentioned in some examples. This is with a 2.0.7 build of oiiio:

import numpy as np
import OpenImageIO as oiio

filename = "foo.exr"
nChannels = 4
xres=512
yres=512
specs = []
specs.append(oiio.ImageSpec(xres, yres, nChannels, "float"))
specs.append(oiio.ImageSpec(xres, yres, nChannels, "float"))
specs.append(oiio.ImageSpec(xres, yres, nChannels, "float"))
specs.append(oiio.ImageSpec(xres, yres, nChannels, "float"))
specs.append(oiio.ImageSpec(xres, yres, nChannels, "float"))
nSubimages = len(specs)
pixels = []
pixels.append(np.array([1]*nChannels*xres*yres,np.float32))
pixels.append(np.array([1]*nChannels*xres*yres,np.float32))
pixels.append(np.array([1]*nChannels*xres*yres,np.float32))
pixels.append(np.array([1]*nChannels*xres*yres,np.float32))
pixels.append(np.array([1]*nChannels*xres*yres,np.float32))
names=[]
names.append("beauty")
names.append("lpe_1")
names.append("lpe_2")
names.append("lpe_3")
names.append("lpe_4")

output = oiio.ImageOutput.create(filename)
output.open(filename, specs)
for i, s in enumerate(specs):
    #s.getattribute('oiio:subimagename')
    s.attribute("name",names[i])
    s.attribute("oiio:subimagename",names[i])
    if i > 0:
        output.open(filename, s, "AppendSubimage")
    output.write_image(pixels[i])
output.close()

[lgritz]

Before I dive deep into this, can you please try this with OIIO 2.2 and see if it's something that was already fixed long ago?