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i was trying to draw a large grid (64x64) and it was slow, so i tweaked the draw() function to skip calculating validOptions for cells that weren't adjacent to any other collapsed cells
// if ZERO adjacent cells are collapsed, skip for now...
let at_least_one_collapsed = false;
for(neighbor of [
j > 0 ? grid[i + (j - 1) * DIM] : null, // up
i < DIM - 1 ? grid[i + 1 + j * DIM] : null, // right
j < DIM - 1 ? grid[i + (j + 1) * DIM] : null, // down
i > 0 ? grid[i - 1 + j * DIM] : null // left
]){
if(neighbor?.collapsed){
at_least_one_collapsed = true;
}
}
if(!at_least_one_collapsed){
nextGrid[index] = new Cell(tiles.length, index); //grid[index];
continue;
}
I also implemented naive backtracking, naive in the sense that it goes backwards step by step, instead of kind of propagating re-picking options in the local neighborhood of a cell with 0 options. that would be the more efficient way. gonna try to implement that next...
i was trying to draw a large grid (64x64) and it was slow, so i tweaked the
draw()
function to skip calculating validOptions for cells that weren't adjacent to any other collapsed cellsyou can test it out on CodePen here: https://codepen.io/jakedowns/pen/PoRbeGQ
I also implemented naive backtracking, naive in the sense that it goes backwards step by step, instead of kind of propagating re-picking options in the local neighborhood of a cell with 0 options. that would be the more efficient way. gonna try to implement that next...
https://twitter.com/i/status/1547662617749045250
chrome-hbznzh1xzk-klwyklmh_hm3twhOG.mp4
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