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想问下为什么 pop函数里面(包括popTo)都有一个先remove再 popBackStack的逻辑,这里只做popBackStack 应该就有remove的效果,一直没看明白是为什么,求大佬解惑 In addition, we do not accept issues unrelated to Fragmentation.
The text was updated successfully, but these errors were encountered:
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Following information can help us to resolve the issue faster.
想问下为什么 pop函数里面(包括popTo)都有一个先remove再 popBackStack的逻辑,这里只做popBackStack 应该就有remove的效果,一直没看明白是为什么,求大佬解惑
In addition, we do not accept issues unrelated to Fragmentation.
The text was updated successfully, but these errors were encountered: