Main.java

package com.liaoguoyin.pat.团体程序设计天梯赛.L1030;

import java.util.ArrayList;
import java.util.Scanner;

/**
 * 我这解法有点暴力，真正意义上它想考察的应该是 队列
 */
public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int N = scanner.nextInt();
        ArrayList<String> boy = new ArrayList<>();
        ArrayList<String> gril = new ArrayList<>();
        scanner.nextLine();
        int[] order = new int[N / 2];

        for (int i = 0; i < N; i++) {
            String str = scanner.nextLine();
            //译者注: 性别的英文为 gender. 有很多词是有固定翻译的, 需要平时积累.
            int sex = Integer.parseInt(str.split(" ")[0]);// get性别参数

            if (i < N / 2)
                order[i] = sex;// 获取正向顺序

            String name = str.split(" ")[1];// get名字

            if (sex == 0)
                gril.add(name);
            else if (sex == 1)
                boy.add(name);
        }

        int countboy = 0, countgril = 0;
        // System.out.println(Arrays.toString(order));
        for (int i = 0; i < boy.size(); i++) {
            if (order[i] == 0) {
                //译者注: 遇到与空格什么的符号拼接时, 尽可能使用 String.format 或者 printf 以提升可读性
                System.out.println(gril.get(countgril) + " " + boy.get(boy.size() - countgril - 1));
                countgril++;
            }
            if (order[i] == 1) {
                System.out.println(boy.get(countboy) + " " + gril.get(gril.size() - countboy - 1));
                countboy++;
            }
        }
    }
}