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'continue' is treated as a keyword even when it's disabled on LuaSyntaxOptions #127

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waneck opened this issue Apr 24, 2024 · 0 comments
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waneck commented Apr 24, 2024

Describe the bug
continue is treated as a keyword even when it's disabled on LuaSyntaxOptions

To Reproduce

using Loretta.CodeAnalysis.Lua;
using Loretta.CodeAnalysis;

var parseOptions = new LuaParseOptions(LuaSyntaxOptions.Lua51).WithDocumentationMode(DocumentationMode.Parse);

// parse
var lorettaAst = LuaSyntaxTree.ParseText(@"
local continue = true

if continue then
    continue = false
end
", parseOptions, "test.lua");

foreach (var exc in lorettaAst.GetDiagnostics())
{
    Console.WriteLine(exc.ToString()); 
}

this code generates the following diagnostics:

test.lua(2,7): error LUA1000: Identifier expected; 'continue' is a keyword
test.lua(2,16): error LUA1012: Invalid statement
test.lua(2,16): error LUA1012: Invalid statement
test.lua(4,4): error LUA1011: Invalid expression part 'continue'
test.lua(4,4): error LUA1006: Syntax error, 'then' expected
test.lua(4,11): error LUA1012: Invalid statement
test.lua(5,14): error LUA1012: Invalid statement
test.lua(5,14): error LUA1012: Invalid statement

Expected behavior
Since Lua 5.1 is defined, no error is expected

Additional context
Loretta Version: Happens both on 0.2.13-nightly1 and 0.2.12

@waneck waneck added the bug Something isn't working label Apr 24, 2024
@GGG-KILLER GGG-KILLER moved this to Todo in Language Support Apr 26, 2024
@GGG-KILLER GGG-KILLER added this to the v0.2.12 milestone Apr 26, 2024
@GGG-KILLER GGG-KILLER self-assigned this Apr 26, 2024
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