forked from Light-City/CPlusPlusThings
-
Notifications
You must be signed in to change notification settings - Fork 0
/
函数综合练习题.cpp
61 lines (53 loc) · 1.34 KB
/
函数综合练习题.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
/*
一圆型游泳池如图所示,现在需在其周围建一圆型过道,并在其四周围上栅栏。栅栏价格为35元/米,过道造价为20元/平方米。
过道宽度为3米,游泳池半径由键盘输入。要求编程计算并输出过道和栅栏的造价。
图形描述:大圆嵌套小圆:
小圆在大圆中间,小圆为游泳池,大圆与小圆间隔为过道。
*/
#include<iostream>
using namespace std;
const float PI=3.14159;
const float FencePrice=35;
const float ConcretePrice=20;
class Circle
{
private:
float radius;
public:
Circle(float r);
float Circumference() const;
float Area() const;
};
Circle::Circle(float r)
{
radius=r;
}
// 计算圆的周长
float Circle::Circumference() const
{
return 2 * PI * radius;
}
// 计算圆的面积
float Circle::Area() const
{
return PI * radius * radius;
}
int main(int argc, char const *argv[])
{
float radius;
float FenceCost, ConcreteCost;
// 提示用户输入半径
cout<<"Enter the radius of the pool: ";
cin>>radius;
// 声明 Circle 对象
Circle Pool(radius);
Circle PoolRim(radius + 3);
// 计算栅栏造价并输出
FenceCost = PoolRim.Circumference() * FencePrice;
cout << "Fencing Cost is ¥" << FenceCost << endl;
// 计算过道造价并输出
ConcreteCost = (PoolRim.Area() - Pool.Area())*ConcretePrice;
cout << "Concrete Cost is ¥" << ConcreteCost << endl;
system("pause");
return 0;
}