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面试题19之二叉树的镜像_MirrorOfBinaryTree.cpp
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面试题19之二叉树的镜像_MirrorOfBinaryTree.cpp
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// MirrorOfBinaryTree.cpp : Defines the entry point for the console application.
//
// 《剑指Offer——名企面试官精讲典型编程题》代码
// 著作权所有者:何海涛
#include "stdafx.h"
#include "Utilities\BinaryTree.h"
#include <stack>
void MirrorRecursively(BinaryTreeNode *pNode)
{
if((pNode == NULL) || (pNode->m_pLeft == NULL && pNode->m_pRight))
return;
BinaryTreeNode *pTemp = pNode->m_pLeft;
pNode->m_pLeft = pNode->m_pRight;
pNode->m_pRight = pTemp;
if(pNode->m_pLeft)
MirrorRecursively(pNode->m_pLeft);
if(pNode->m_pRight)
MirrorRecursively(pNode->m_pRight);
}
void MirrorIteratively(BinaryTreeNode* pRoot)
{
if(pRoot == NULL)
return;
std::stack<BinaryTreeNode*> stackTreeNode;
stackTreeNode.push(pRoot);
while(stackTreeNode.size() > 0)
{
BinaryTreeNode *pNode = stackTreeNode.top();
stackTreeNode.pop();
BinaryTreeNode *pTemp = pNode->m_pLeft;
pNode->m_pLeft = pNode->m_pRight;
pNode->m_pRight = pTemp;
if(pNode->m_pLeft)
stackTreeNode.push(pNode->m_pLeft);
if(pNode->m_pRight)
stackTreeNode.push(pNode->m_pRight);
}
}
// ====================测试代码====================
// 测试完全二叉树:除了叶子节点,其他节点都有两个子节点
// 8
// 6 10
// 5 7 9 11
void Test1()
{
printf("=====Test1 starts:=====\n");
BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8);
BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6);
BinaryTreeNode* pNode10 = CreateBinaryTreeNode(10);
BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5);
BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7);
BinaryTreeNode* pNode9 = CreateBinaryTreeNode(9);
BinaryTreeNode* pNode11 = CreateBinaryTreeNode(11);
ConnectTreeNodes(pNode8, pNode6, pNode10);
ConnectTreeNodes(pNode6, pNode5, pNode7);
ConnectTreeNodes(pNode10, pNode9, pNode11);
PrintTree(pNode8);
printf("=====Test1: MirrorRecursively=====\n");
MirrorRecursively(pNode8);
PrintTree(pNode8);
printf("=====Test1: MirrorIteratively=====\n");
MirrorIteratively(pNode8);
PrintTree(pNode8);
DestroyTree(pNode8);
}
// 测试二叉树:出叶子结点之外,左右的结点都有且只有一个左子结点
// 8
// 7
// 6
// 5
// 4
void Test2()
{
printf("=====Test2 starts:=====\n");
BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8);
BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7);
BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6);
BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5);
BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4);
ConnectTreeNodes(pNode8, pNode7, NULL);
ConnectTreeNodes(pNode7, pNode6, NULL);
ConnectTreeNodes(pNode6, pNode5, NULL);
ConnectTreeNodes(pNode5, pNode4, NULL);
PrintTree(pNode8);
printf("=====Test2: MirrorRecursively=====\n");
MirrorRecursively(pNode8);
PrintTree(pNode8);
printf("=====Test2: MirrorIteratively=====\n");
MirrorIteratively(pNode8);
PrintTree(pNode8);
DestroyTree(pNode8);
}
// 测试二叉树:出叶子结点之外,左右的结点都有且只有一个右子结点
// 8
// 7
// 6
// 5
// 4
void Test3()
{
printf("=====Test3 starts:=====\n");
BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8);
BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7);
BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6);
BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5);
BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4);
ConnectTreeNodes(pNode8, NULL, pNode7);
ConnectTreeNodes(pNode7, NULL, pNode6);
ConnectTreeNodes(pNode6, NULL, pNode5);
ConnectTreeNodes(pNode5, NULL, pNode4);
PrintTree(pNode8);
printf("=====Test3: MirrorRecursively=====\n");
MirrorRecursively(pNode8);
PrintTree(pNode8);
printf("=====Test3: MirrorIteratively=====\n");
MirrorIteratively(pNode8);
PrintTree(pNode8);
DestroyTree(pNode8);
}
// 测试空二叉树:根结点为空指针
void Test4()
{
printf("=====Test4 starts:=====\n");
BinaryTreeNode* pNode = NULL;
PrintTree(pNode);
printf("=====Test4: MirrorRecursively=====\n");
MirrorRecursively(pNode);
PrintTree(pNode);
printf("=====Test4: MirrorIteratively=====\n");
MirrorIteratively(pNode);
PrintTree(pNode);
}
// 测试只有一个结点的二叉树
void Test5()
{
printf("=====Test5 starts:=====\n");
BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8);
PrintTree(pNode8);
printf("=====Test4: MirrorRecursively=====\n");
MirrorRecursively(pNode8);
PrintTree(pNode8);
printf("=====Test4: MirrorIteratively=====\n");
MirrorIteratively(pNode8);
PrintTree(pNode8);
}
int _tmain(int argc, _TCHAR* argv[])
{
Test1();
Test2();
Test3();
Test4();
Test5();
return 0;
}