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面试题45之圆圈中最后剩下的数字_LastNumberInCircle.cpp
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面试题45之圆圈中最后剩下的数字_LastNumberInCircle.cpp
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// LastNumberInCircle.cpp : Defines the entry point for the console application.
//
// 《剑指Offer——名企面试官精讲典型编程题》代码
// 著作权所有者:何海涛
#include "stdafx.h"
#include <list>
using namespace std;
// ====================方法1====================
int LastRemaining_Solution1(unsigned int n, unsigned int m)
{
if(n < 1 || m < 1)
return -1;
unsigned int i = 0;
list<int> numbers;
for(i = 0; i < n; ++ i)
numbers.push_back(i);
list<int>::iterator current = numbers.begin();
while(numbers.size() > 1)
{
for(int i = 1; i < m; ++ i)
{
current ++;
if(current == numbers.end())
current = numbers.begin();
}
list<int>::iterator next = ++ current;
if(next == numbers.end())
next = numbers.begin();
-- current;
numbers.erase(current);
current = next;
}
return *(current);
}
// ====================方法2====================
int LastRemaining_Solution2(unsigned int n, unsigned int m)
{
if(n < 1 || m < 1)
return -1;
int last = 0;
for (int i = 2; i <= n; i ++)
last = (last + m) % i;
return last;
}
// ====================测试代码====================
void Test(char* testName, unsigned int n, unsigned int m, int expected)
{
if(testName != NULL)
printf("%s begins: \n", testName);
if(LastRemaining_Solution1(n, m) == expected)
printf("Solution1 passed.\n");
else
printf("Solution1 failed.\n");
if(LastRemaining_Solution2(n, m) == expected)
printf("Solution2 passed.\n");
else
printf("Solution2 failed.\n");
printf("\n");
}
void Test1()
{
Test("Test1", 5, 3, 3);
}
void Test2()
{
Test("Test2", 5, 2, 2);
}
void Test3()
{
Test("Test3", 6, 7, 4);
}
void Test4()
{
Test("Test4", 6, 6, 3);
}
void Test5()
{
Test("Test5", 0, 0, -1);
}
void Test6()
{
Test("Test6", 4000, 997, 1027);
}
int _tmain(int argc, _TCHAR* argv[])
{
Test1();
Test2();
Test3();
Test4();
Test5();
Test6();
return 0;
}