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index.js
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/*
* @lc app=leetcode id=103 lang=javascript
*
* [103] Binary Tree Zigzag Level Order Traversal
*
* https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/description/
*
* algorithms
* Medium (40.15%)
* Total Accepted: 299.3K
* Total Submissions: 664.2K
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* Given a binary tree, return the zigzag level order traversal of its nodes'
* values. (ie, from left to right, then right to left for the next level and
* alternate between).
*
*
* For example:
* Given binary tree [3,9,20,null,null,15,7],
*
* 3
* / \
* 9 20
* / \
* 15 7
*
*
*
* return its zigzag level order traversal as:
*
* [
* [3],
* [20,9],
* [15,7]
* ]
*
*
*/
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var zigzagLevelOrder = function(root) {
if (!root) {
return [];
}
const res = [];
let direction = true;
bfs([root]);
function bfs(nodes) {
if (!nodes.length) {
return
}
if (direction) {
res.push(nodes.map((node) => node.val));
} else {
res.push(nodes.map((node) => node.val).reverse());
}
direction = !direction;
const nextRows = [];
nodes.forEach((node) => {
node.left && nextRows.push(node.left);
node.right && nextRows.push(node.right);
});
bfs(nextRows);
}
return res;
};
const { make_tree } = require('../utils');
const [ root ] = make_tree([3,9,20,null,null,15,7], [0]);
console.log(zigzagLevelOrder(root));
module.exports = {
id:'103',
title:'Binary Tree Zigzag Level Order Traversal',
url:'https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/description/',
difficulty:'Medium',
}