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index.js
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/*
* @lc app=leetcode id=174 lang=javascript
*
* [174] Dungeon Game
*
* https://leetcode.com/problems/dungeon-game/description/
*
* algorithms
* Hard (26.30%)
* Total Accepted: 62.9K
* Total Submissions: 236.4K
* Testcase Example: '[[-2,-3,3],[-5,-10,1],[10,30,-5]]'
*
* table.dungeon, .dungeon th, .dungeon td {
* border:3px solid black;
* }
*
* .dungeon th, .dungeon td {
* text-align: center;
* height: 70px;
* width: 70px;
* }
*
* The demons had captured the princess (P) and imprisoned her in the
* bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid
* out in a 2D grid. Our valiant knight (K) was initially positioned in the
* top-left room and must fight his way through the dungeon to rescue the
* princess.
*
* The knight has an initial health point represented by a positive integer. If
* at any point his health point drops to 0 or below, he dies immediately.
*
* Some of the rooms are guarded by demons, so the knight loses health
* (negative integers) upon entering these rooms; other rooms are either empty
* (0's) or contain magic orbs that increase the knight's health (positive
* integers).
*
* In order to reach the princess as quickly as possible, the knight decides to
* move only rightward or downward in each step.
*
*
*
* Write a function to determine the knight's minimum initial health so that he
* is able to rescue the princess.
*
* For example, given the dungeon below, the initial health of the knight must
* be at least 7 if he follows the optimal path RIGHT-> RIGHT -> DOWN ->
* DOWN.
*
*
*
*
* -2 (K)
* -3
* 3
*
*
* -5
* -10
* 1
*
*
* 10
* 30
* -5 (P)
*
*
*
*
*
*
* Note:
*
*
* The knight's health has no upper bound.
* Any room can contain threats or power-ups, even the first room the knight
* enters and the bottom-right room where the princess is imprisoned.
*
*
*/
/**
* 思路
* 我们设dp[i][j]为,从坐标i,j出发,到右下角所需要的最优血量
*
* 对于dp[i][j]我们只能选择往右边或者往下边走,
*
* 往右时 dp[i][j] = dp[i][j + 1] - dungeon[i][j]
* 往下时 dp[i][j] = dp[i+1][j] - dungeon[i][j]
* 我们需要选两者中需要血最少的那个,并且还要保证血量不少于1
*
* dp[i][j] = Max(Min(dp[i][j+1], dp[i+1][j]) - dungeon[i][j], 1)
*
* 根据题目最右下时的血量为1
*
* @param {number[][]} dungeon
* @return {number}
*/
var calculateMinimumHP = function(dungeon) {
const dp = dungeon.map((item) => []);
let lastI = dungeon.length - 1;
let lastJ = dungeon[lastI].length - 1;
dp[lastI][lastJ] = Math.max(1 - dungeon[lastI][lastJ], 1);
for (let j = lastJ - 1; j >=0; j--) {
dp[lastI][j] = Math.max(dp[lastI][j + 1] - dungeon[lastI][j], 1);
}
for (let i = lastI - 1; i >=0; i--) {
dp[i][lastJ] = Math.max(dp[i + 1][lastJ] - dungeon[i][lastJ], 1);
}
for (let i = lastI - 1; i >=0; i--) {
for (let j = lastJ - 1; j >=0; j--) {
dp[i][j] = Math.max(Math.min(dp[i + 1][j], dp[i][j + 1]) - dungeon[i][j], 1);
}
}
return dp[0][0];
};
// const test = [[-2,-3,3],[-5,-10,1],[10,30,-5]];
const test = [[1,-3,3],[0,-2,0],[-3,-3,-3]];
console.log(calculateMinimumHP(test));
module.exports = {
id:'174',
title:'Dungeon Game',
url:'https://leetcode.com/problems/dungeon-game/description/',
difficulty:'Hard',
}