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index.js
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/*
* @lc app=leetcode id=57 lang=javascript
*
* [57] Insert Interval
*
* https://leetcode.com/problems/insert-interval/description/
*
* algorithms
* Hard (30.61%)
* Total Accepted: 166.3K
* Total Submissions: 539.5K
* Testcase Example: '[[1,3],[6,9]]\n[2,5]'
*
* Given a set of non-overlapping intervals, insert a new interval into the
* intervals (merge if necessary).
*
* You may assume that the intervals were initially sorted according to their
* start times.
*
* Example 1:
*
*
* Input: intervals = [[1,3],[6,9]], newInterval = [2,5]
* Output: [[1,5],[6,9]]
*
*
* Example 2:
*
*
* Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]
* Output: [[1,2],[3,10],[12,16]]
* Explanation: Because the new interval [4,8] overlaps with
* [3,5],[6,7],[8,10].
*
*/
/**
* Definition for an interval.
* function Interval(start, end) {
* this.start = start;
* this.end = end;
* }
*/
/**思路:
*
* 不断的融合,如果需要融合时就把当前项去掉,最后把融合的项插入到指定位置
*
* @param {Interval[]} intervals
* @param {Interval} newInterval
* @return {Interval[]}
*/
var insert = function(intervals, newInterval) {
for (let i = intervals.length - 1; i >=0; i--) {
const mergeResult = needMerge(intervals[i], newInterval);
if (mergeResult) {
newInterval.start = mergeResult.start;
newInterval.end = mergeResult.end;
intervals.splice(i, 1);
}
}
let insertIndex = 0;
for (;insertIndex < intervals.length; insertIndex++) {
if (intervals[insertIndex].start > newInterval.start) {
break;
}
}
intervals.splice(insertIndex, 0, newInterval);
return intervals;
function needMerge(first, second) {
const minStart = Math.min(first.start, second.start);
const maxEnd = Math.max(first.end, second.end);
if ((maxEnd - minStart) <= (first.end - first.start + second.end - second.start)) {
return {
start:minStart,
end:maxEnd,
};
}
return false;
}
};
module.exports = {
id:'57',
title:'Insert Interval',
url:'https://leetcode.com/problems/insert-interval/description/',
difficulty:'Hard',
}