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index.js
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/*
* @lc app=leetcode id=79 lang=javascript
*
* [79] Word Search
*
* https://leetcode.com/problems/word-search/description/
*
* algorithms
* Medium (30.15%)
* Total Accepted: 395.6K
* Total Submissions: 1.2M
* Testcase Example: '[["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]]\n"ABCCED"'
*
* Given a 2D board and a word, find if the word exists in the grid.
*
* The word can be constructed from letters of sequentially adjacent cell,
* where "adjacent" cells are those horizontally or vertically neighboring. The
* same letter cell may not be used more than once.
*
* Example:
*
*
* board =
* [
* ['A','B','C','E'],
* ['S','F','C','S'],
* ['A','D','E','E']
* ]
*
* Given word = "ABCCED", return true.
* Given word = "SEE", return true.
* Given word = "ABCB", return false.
*
*
*/
/**
* @param {string[][]} board
* @param {string} word
* @return {boolean}
*/
var exist = function(board, word) {
if (board.length === 0) {
return false;
}
for (let i = 0; i < board.length; i++) {
for (let j = 0; j < board[i].length; j++) {
if (search(i, j, 0)) {
return true;
}
}
}
return false;
function search(i, j, d) {
if (
i >= board.length ||
i < 0 ||
j < 0 ||
j >= board[0].length ||
word[d] !== board[i][j]
) {
return false;
}
if (d + 1 === word.length) {
return true;
}
const cur = board[i][j];
board[i][j] = '';
if (
search(i - 1, j, d + 1) ||
search(i, j - 1, d + 1) ||
search(i + 1, j, d + 1) ||
search(i, j + 1, d + 1)
) {
board[i][j] = cur;
return true;
}
board[i][j] = cur;
return false;
}
};
const board = [
['A','B','C','E'],
['S','F','C','S'],
['A','D','E','E']
];
console.log(exist(board, 'ABCCED'));
console.log(exist(board, 'SEE'));
console.log(exist(board, 'ABCB'));
module.exports = {
id:'79',
title:'Word Search',
url:'https://leetcode.com/problems/word-search/description/',
difficulty:'Medium',
}