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frog-position-after-t-seconds.cpp
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frog-position-after-t-seconds.cpp
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// Time: O(n)
// Space: O(n)
// bfs solution with better precision
class Solution {
public:
double frogPosition(int n, vector<vector<int>>& edges, int t, int target) {
unordered_map<int, vector<int>> G;
G[1] = {};
for (const auto& edge : edges) {
G[edge[0]].emplace_back(edge[1]);
G[edge[1]].emplace_back(edge[0]);
}
vector<tuple<int, int, int, int>> stk = {{t, 1, 0, 1}};
while (!stk.empty()) {
vector<tuple<int, int, int, int>> new_stk;
while (!stk.empty()) {
const auto [t, node, parent, choices] = stk.back(); stk.pop_back();
if (!t || !(G.at(node).size() - int(parent != 0))) {
if (node == target) {
return 1.0 / choices;
}
continue;
}
for (const auto& child : G.at(node)) {
if (child == parent) {
continue;
}
new_stk.emplace_back(t - 1, child, node,
choices * (G.at(node).size() - int(parent != 0)));
}
}
stk = move(new_stk);
}
return 0.0;
}
};
// Time: O(n)
// Space: O(n)
// dfs solution with stack with better precision
class Solution2 {
public:
double frogPosition(int n, vector<vector<int>>& edges, int t, int target) {
unordered_map<int, vector<int>> G;
G[1] = {};
for (const auto& edge : edges) {
G[edge[0]].emplace_back(edge[1]);
G[edge[1]].emplace_back(edge[0]);
}
vector<tuple<int, int, int, int>> stk = {{t, 1, 0, 1}};
while (!stk.empty()) {
const auto [t, node, parent, choices] = stk.back(); stk.pop_back();
if (!t || !(G.at(node).size() - int(parent != 0))) {
if (node == target) {
return 1.0 / choices;
}
continue;
}
for (const auto& child : G.at(node)) {
if (child == parent) {
continue;
}
stk.emplace_back(t - 1, child, node,
choices * (G.at(node).size() - int(parent != 0)));
}
}
return 0.0;
}
};
// Time: O(n)
// Space: O(n)
// dfs solution with recursion with better precision
class Solution3 {
public:
double frogPosition(int n, vector<vector<int>>& edges, int t, int target) {
unordered_map<int, vector<int>> G;
G[1] = {};
for (const auto& edge : edges) {
G[edge[0]].emplace_back(edge[1]);
G[edge[1]].emplace_back(edge[0]);
}
int choices = dfs(G, target, t, 1, 0);
return choices ? 1.0 / choices : 0.0;
}
private:
int dfs(const unordered_map<int, vector<int>>& G,
int target, int t, int node, int parent) {
if (!t || !(G.at(node).size() - int(parent != 0))) {
return (node == target);
}
int result = 0;
for (const auto& child : G.at(node)) {
if (child == parent) {
continue;
}
if (result = dfs(G, target, t - 1, child, node)) {
break;
}
}
return result * (G.at(node).size() - int(parent != 0));
}
};
// Time: O(n)
// Space: O(n)
// dfs solution with recursion
class Solution4 {
public:
double frogPosition(int n, vector<vector<int>>& edges, int t, int target) {
unordered_map<int, vector<int>> G;
G[1] = {};
for (const auto& edge : edges) {
G[edge[0]].emplace_back(edge[1]);
G[edge[1]].emplace_back(edge[0]);
}
return dfs(G, target, t, 1, 0);
}
private:
double dfs(const unordered_map<int, vector<int>>& G,
int target, int t, int node, int parent) {
if (!t || !(G.at(node).size() - int(parent != 0))) {
return (node == target);
}
double result = 0.0;
for (const auto& child : G.at(node)) {
if (child == parent) {
continue;
}
if (result = dfs(G, target, t - 1, child, node)) {
break;
}
}
return result / (G.at(node).size() - int(parent != 0));
}
};