README.md

SQL Commands Introduction

In this workshop, we will be using basic SQL in a CLI to work with an existing blog database.

Getting Started

Make sure you have installed and setup PostgreSQL: installation instructions

Setting up the workshop database

Clone this workshop and cd into it, then run these commands after using psql:

CREATE DATABASE blog_workshop;

\c blog_workshop - connect to the database

\i init.sql - run SQL build file in blog_workshop (You can also do psql --file init.sql in bash)

Schema Info

You are given the task of creating a blog. A simple blog would have users who can write blog posts, and blog posts that can contain comments and replies.

Users has no direct relationships to other tables, but a blog post has to have an author, so blog_posts has a user_id FOREIGN KEY of users(id).

Comments have to be attached to a blog post, so post_id has a post_id FOREIGN KEY of blog_posts(id).

Users - users

Column	Type	Modifiers
id	serial (translates to integer and AUTO_INCREMENT)	PRIMARY KEY
username	VARCHAR(255)	NOT NULL
age	INTEGER
first_name	VARCHAR(255)
last_name	VARCHAR(255)
location	VARCHAR(255)

Blog Posts - blog_posts

Column	Type	Modifiers
id	SERIAL	PRIMARY KEY
user_id	INTEGER	REFERENCES users(id)
text_content	TEXT

post_comments - post_comments

Column	Type	Modifiers
id	SERIAL	PRIMARY KEY
post_id	INTEGER	REFERENCES blog_posts(id),
reply_to	INTEGER	REFERENCES post_comments(id),
user_id	INTEGER	REFERENCES users(id)
text_content	TEXT

Challenges

1. Using SELECT, retrieve all the information from the users table

Expected Result

id	username	age	first_name	last_name	location
1	Sery1976	28	Alisha	Clayton	Middlehill, UK
2	Notne1991	36	Chelsea	Cross	Sunipol, UK
3	Moull1990	41	Skye	Hobbs	Wanlip, UK
4	Spont1935	72	Matthew	Griffin	Saxilby, UK
5	Precand	19	Erin	Gould	Stanton, UK
6	Ovion1948	53	Reece	Sheppard	Easton in Gordano, UK
7	Thresuall	21	Daniel	Grant	Slackhall, UK
8	Brity1971	23	Daniel	Brennan	Saxilby, UK

2. Using SELECT, retrieve a list of only username and location from the users table

Expected Result

username	location
Sery1976	Middlehill, UK
Notne1991	Sunipol, UK
Moull1990	Wanlip, UK
Spont1935	Saxilby, UK
Precand	Stanton, UK
Ovion1948	Easton in Gordano, UK
Thresuall	Slackhall, UK
Brity1971	Saxilby, UK

3. Using SELECT and WHERE, retrieve a list of users with all their data who are older than 50

Expected Result

id	username	age	first_name	last_name	location
4	Spont1935	72	Matthew	Griffin	Saxilby, UK
6	Ovion1948	53	Reece	Sheppard	Easton in Gordano, UK

4. Using SELECT and WHERE, retrieve the first, last name and location of the user who lives in Saxilby, UK and is older than 40.

Expected Result

first_name	last_name	location
Matthew	Griffin	Saxilby, UK

5. Using the WHERE operator, LIKE, retrieve a list of user IDs that have posted blog posts that contain the word departure.

Expected Result

user_id
2
3

6. Imagine an API request is made for blog posts with the IDs 3 and 6. Using WHERE and IN, show the blog posts' user id and text content.

Expected Result

user_id	text_content
3	Far stairs now coming bed oppose hunted become his. You zealously departure had procuring suspicion. Books whose front would purse if be do decay.
6	Etiam in est nec neque dapibus pretium in in lectus. Proin consequat velit quis magna aliquam tristique. Sed ultricies nulla vel feugiat mattis. Aliquam erat volutpat. Aliquam ac vehicula diam, eget ultricies nisi.

7. You need to find out which of your users are teenagers and which are not. Using CASE WHEN and AS, show a list of users by their id and a new column called teenager with the values true or false.

Expected Result

id	teenager
1	false
2	false
3	false
4	false
5	true
6	false
7	false
8	false

Using INSERT and UPDATE

So, we have retrieved data from the database. The next exercises will cover adding data

8. Using INSERT INTO, add a blog post with the text "Hello world" to the user with ID 1, then run SELECT text_content FROM blog_posts WHERE user_id=1; to test for the expected result.

Expected Result

text_content
Hello World

9. Using UPDATE, update the blog post from the previous question to change the author to the user with ID 5, then run SELECT user_id FROM blog_posts WHERE text_content='Hello world'; to test for the expected result.

Expected Result

user_id
5

Bonus Question

10. Using INSERT INTO, add a comment with the text Interesting post from the user_id of 3 to the blog post containing the text Peculiar (reply_to will be null), then run SELECT text_content FROM post_comments WHERE post_id = 2; to test for the expected result.

Expected Result

text_content
Interesting post