Rotation angle #100
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Hello! I wonder how EasyIDP deals with image rotation when backward projecting. I mean, if a shape file has a rectangle, which edge will be the top (i.e. defined by the 0-th and 1-st entries of the output image coordinate array) of the resulting crop region? Does the edge between 9 to 12 o'clock become the top? |
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The easyidp doesn't rotate and resize the rectange to get the final position. It can only calcualte a 3D point (x, y, z) to 2D point (x0, y0) on the image And a rectange has 4 vectex, repeat previous step for each vertex to get the final result. |
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Got it. Thank you! |
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The easyidp doesn't rotate and resize the rectange to get the final position.
It can only calcualte a 3D point (x, y, z) to 2D point (x0, y0) on the image
And a rectange has 4 vectex, repeat previous step for each vertex to get the final result.