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234.java
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234.java
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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public boolean isPalindrome(ListNode head) {
ListNode curr = head;
Stack<ListNode> stack = new Stack<>();
if(head==null||head.next==null){
return true;
}
while(curr!=null){
stack.push(curr);
curr=curr.next;
}
curr = head;
// 本质上是翻转以后比较
while(curr!=null){
if(curr.val!=stack.peek().val){
return false;
}
curr=curr.next;
stack.pop();
}
return true;
}
}
// 字符串更加简洁的方法
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public boolean isPalindrome(ListNode head) {
StringBuilder sb = new StringBuilder();
while(head!=null){
sb.append(head.val);
head = head.next;
}
String s1 = sb.toString();
String s2 = sb.reverse().toString();
return s1.equals(s2);
}
}
// 第二次做的方法
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public boolean isPalindrome(ListNode head) {
StringBuilder sb = new StringBuilder();
ListNode cur = head;
while(cur!=null){
sb.append(cur.val);
cur = cur.next;
}
String str = sb.toString();
if(str.equals(sb.reverse().toString()))
return true;
return false;
}
}