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Normally, the VC generator decomposes an invariant into two smaller invariants:
Inv==/\A/\B
Inv is decomposed into:
Inv_0==AInv_1==B
However, if we annotate the invariant with a label, which is quite useful to see what has been violated, then the VC generator does not go inside the expression under the label:
Inv==InInv::/\A/\B
This should be quite easy to fix.
The text was updated successfully, but these errors were encountered:
konnov
changed the title
Labels should not stop VC generator from decomposing an invariant
Labels should not prevent the VC generator from decomposing an invariant
Oct 13, 2024
Normally, the VC generator decomposes an invariant into two smaller invariants:
Inv
is decomposed into:However, if we annotate the invariant with a label, which is quite useful to see what has been violated, then the VC generator does not go inside the expression under the label:
This should be quite easy to fix.
The text was updated successfully, but these errors were encountered: