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Factor out repeated code in conditional type checking #106

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kevin1 opened this issue Dec 1, 2015 · 0 comments
Open

Factor out repeated code in conditional type checking #106

kevin1 opened this issue Dec 1, 2015 · 0 comments

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@kevin1
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kevin1 commented Dec 1, 2015

Introduced in #104

There are three cases (know both, know one, know none) but we handle using 4 cases -- hence, repeated code.

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