2020-03-08 对象合并

[fanmingfei]

不需要考虑浏览器兼容性。

[markmcsong]

function merge(json1, json2) {
  if(!json1 || !json2) return json1 || json2
  const result = {}
  for (let prop in json1) {
    result[prop] = json1[prop]
  }
  for (let prop in json2) {
    // 同名属性值为 Object
    if (Reflect.has(json1, prop) && isObject(json2[prop]) && isObject(json1[prop])) {
      result[prop] = merge(json1[prop], json2[prop])
    } else {
      result[prop] = json2[prop]
    }
  }
  return result
}

const isObject = el => {
  return Object.prototype.toString.call(el) === '[object Object]'
}

[SunYiwen]

function merge(json1,json2){
    const json  = {};
    let propName = Object.keys(json2);
    for(let prop in json1 ){
        json[prop] = json1[prop];
    }
    propName.map(function (item) {
        if(json[item] === undefined){
            json[item] = json2[item];
        }
        else{
            if(typeof json[item] === "object"&& (!Array.isArray(json[item]))){
                json[item] = merge(json[item],json2[item]);
            }
            else{
                json[item] = json2[item];
            }
        }
    })
    return json;
}

[fanmingfei]

function merge(json1, json2) {
  const json = JSON.parse(JSON.stringify(json1))
  const realMerge = (a, b) => {
    for(let key in b) {
      if (Object.prototype.toString.call(a[key]) !== '[object Object]') {
        a[key] = b[key]
      } else {
        realMerge(a[key], b[key])
      }
    }
  }
  realMerge(json, json2)
  return json
 }

[LiZhaji]

 function merge(json1, json2) {
   const json = {...json1}
   for (const key in json2) {
      Object.assign(json, 
      {[key]: Object.prototype.toString.call(json2[key] ) === '[object Object]' 
      ? merge(json1[key], json2[key]) : json2[key]})
   }
   return json
 }
merge(json1, json2)

[xiaosen7]

function merge(...objs) {
return objs.reduceRight((right, left) => {
for (const key in right) {
if ((Object.prototype.toString.call(right[key]) === '[object Object]') && (Object.prototype.toString.call(left[key]) === '[object Object]')) {
merge(left[key], right[key]);
} else {
left[key] = right[key];
}
}
return left;
});
}

[terrykingcha]

function getType(value) {
  try {
    return Object.prototype.toString.call(value).match(/\b(\w+)\]$/)[1];
  } catch(e) {
    return '';
  }
}

function merge(source, target) {
  const result = {};
  const keys = Object.keys(source);
  
  Object.keys(target).forEach(key => !keys.includes(key) && keys.push(key));
  

  for (const key of keys) {
    const sourceType = getType(source[key]);
    const targetType = getType(target[key]);
    if (sourceType === targetType) {
      if (sourceType === 'Object') {
        result[key] = merge(source[key], target[key]);
      } else {
        result[key] = target[key];
      }
    } else if (targetType === 'Undefined') {
       result[key] = source[key];
    } else if (sourceType === 'Undefined') {
       result[key] = target[key];
    } else {
       throw new Error('wrong data sturcture');
    }
  }

  return result;
}

[KobeBeyond]

function merge(target, source) {
return Object.assign(target, source)
}
// 详见https://developer.mozilla.org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Object/assign

[fanmingfei]

function merge(target, source) {
return Object.assign(target, source)
}
// 详见https://developer.mozilla.org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Object/assign

你这个不太行吧，对象里面但对象是要合并但。

[fanmingfei]

function getType(value) {
  try {
    return Object.prototype.toString.call(value).match(/\b(\w+)\]$/)[1];
  } catch(e) {
    return '';
  }
}

function merge(source, target) {
  const result = {};
  const keys = Object.keys(source);
  
  Object.keys(target).forEach(key => !keys.includes(key) && keys.push(key));
  

  for (const key of keys) {
    const sourceType = getType(source[key]);
    const targetType = getType(target[key]);
    if (sourceType === targetType) {
      if (sourceType === 'Object') {
        result[key] = merge(source[key], target[key]);
      } else {
        result[key] = target[key];
      }
    } else if (targetType === 'Undefined') {
       result[key] = source[key];
    } else if (sourceType === 'Undefined') {
       result[key] = target[key];
    } else {
       throw new Error('wrong data sturcture');
    }
  }

  return result;
}

const json1 = {
a: {a:1}
}
const json2 = {
a: 1
}

@terrykingcha 不能用数字覆盖对象。

[KobeBeyond]

function merge(target, source) {
return Object.assign(target, source)
}
// 详见https://developer.mozilla.org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Object/assign

你这个不太行吧，对象里面但对象是要合并但。

嗯你说得对！我没看清题🤪