Given a linked list, swap every two adjacent nodes and return its head.
You may not modify the values in the list's nodes, only nodes itself may be changed.
Given 1->2->3->4, you should return the list as 2->1->4->3.
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def swapPairs(self, head: ListNode) -> ListNode:
if head and head.next:
tmp = head.next.next
head.next.next = head
head = head.next
head.next.next = self.swapPairs(tmp)
return head