Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse the first k characters and left the other as original.
Input: s = "abcdefg", k = 2 Output: "bacdfeg"
- The string consists of lower English letters only.
- Length of the given string and k will in the range [1, 10000]
class Solution:
def reverseStr(self, s: str, k: int) -> str:
s_list = list(s)
for i in range(0, len(s), 2 * k):
j = min(i + k - 1, len(s) - 1)
while i < j:
s_list[i], s_list[j] = s_list[j], s_list[i]
i += 1
j -= 1
return ''.join(s_list)