Given an array of integers nums
and an integer k
, return the total number of continuous subarrays whose sum equals to k
.
Input: nums = [1,1,1], k = 2 Output: 2
Input: nums = [1,2,3], k = 3 Output: 2
1 <= nums.length <= 2 * 104
-1000 <= nums[i] <= 1000
-107 <= k <= 107
use std::collections::HashMap;
impl Solution {
pub fn subarray_sum(nums: Vec<i32>, k: i32) -> i32 {
let mut count = vec![(0, 1)].into_iter().collect::<HashMap<_, _>>();
let mut sum = 0;
let mut ret = 0;
for num in nums {
sum += num;
ret += count.get(&(sum - k)).unwrap_or(&0);
*count.entry(sum).or_insert(0) += 1;
}
ret
}
}