Given a string s
and an array of strings words
, return the number of words[i]
that is a subsequence of s
.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
- For example,
"ace"
is a subsequence of"abcde"
.
Input: s = "abcde", words = ["a","bb","acd","ace"] Output: 3 Explanation: There are three strings in words that are a subsequence of s: "a", "acd", "ace".
Input: s = "dsahjpjauf", words = ["ahjpjau","ja","ahbwzgqnuk","tnmlanowax"] Output: 2
1 <= s.length <= 5 * 104
1 <= words.length <= 5000
1 <= words[i].length <= 50
s
andwords[i]
consist of only lowercase English letters.
impl Solution {
pub fn num_matching_subseq(s: String, words: Vec<String>) -> i32 {
let mut indices = vec![vec![]; 26];
let mut ret = 0;
for (i, c) in s.bytes().enumerate() {
indices[(c - b'a') as usize].push(i);
}
for word in &words {
let mut i = 0;
let mut flag = true;
for c in word.bytes() {
match indices[(c - b'a') as usize].binary_search(&i) {
Err(j) if j == indices[(c - b'a') as usize].len() => {
flag = false;
break;
}
Ok(j) | Err(j) => i = indices[(c - b'a') as usize][j] + 1,
}
}
ret += flag as i32;
}
ret
}
}