Given the root of a binary search tree with distinct values, modify it so that every node
has a new value equal to the sum of the values of the original tree that are greater than or equal to node.val
.
As a reminder, a binary search tree is a tree that satisfies these constraints:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Input: [4,1,6,0,2,5,7,null,null,null,3,null,null,null,8] Output: [30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]
- The number of nodes in the tree is between
1
and100
. - Each node will have value between
0
and100
. - The given tree is a binary search tree.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def bstToGst(self, root: TreeNode) -> TreeNode:
stack = []
curr = root
sum = 0
while stack or curr:
while curr:
stack.append(curr)
curr = curr.right
curr = stack.pop()
sum += curr.val
curr.val = sum
curr = curr.left
return root