README.md

1154. Day of the Year

Given a string date representing a Gregorian calendar date formatted as YYYY-MM-DD, return the day number of the year.

Example 1:

Input: date = "2019-01-09"
Output: 9
Explanation: Given date is the 9th day of the year in 2019.

Example 2:

Input: date = "2019-02-10"
Output: 41

Example 3:

Input: date = "2003-03-01"
Output: 60

Example 4:

Input: date = "2004-03-01"
Output: 61

Constraints:

• date.length == 10
• date[4] == date[7] == '-', and all other date[i]'s are digits
• date represents a calendar date between Jan 1st, 1900 and Dec 31, 2019.

Solutions (Rust)

1. Solution

impl Solution {
    pub fn day_of_year(date: String) -> i32 {
        let v: Vec<i32> = date.split('-').map(|s| s.parse().unwrap()).collect();
        let mut m = vec![31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30];
        let mut ans = v[2];
        if (v[0] % 4 == 0 && v[0] % 100 != 0) || v[0] % 400 == 0 {
            m[1] += 1;
        }
        for i in 1..v[1] {
            ans += m[i as usize - 1];
        }
        ans
    }
}