You are given two non-increasing 0-indexed integer arrays nums1
and nums2
.
A pair of indices (i, j)
, where 0 <= i < nums1.length
and 0 <= j < nums2.length
, is valid if both i <= j
and nums1[i] <= nums2[j]
. The distance of the pair is j - i
.
Return the maximum distance of any valid pair (i, j)
. If there are no valid pairs, return 0
.
An array arr
is non-increasing if arr[i-1] >= arr[i]
for every 1 <= i < arr.length
.
Input: nums1 = [55,30,5,4,2], nums2 = [100,20,10,10,5] Output: 2 Explanation: The valid pairs are (0,0), (2,2), (2,3), (2,4), (3,3), (3,4), and (4,4). The maximum distance is 2 with pair (2,4).
Input: nums1 = [2,2,2], nums2 = [10,10,1] Output: 1 Explanation: The valid pairs are (0,0), (0,1), and (1,1). The maximum distance is 1 with pair (0,1).
Input: nums1 = [30,29,19,5], nums2 = [25,25,25,25,25] Output: 2 Explanation: The valid pairs are (2,2), (2,3), (2,4), (3,3), and (3,4). The maximum distance is 2 with pair (2,4).
1 <= nums1.length, nums2.length <= 105
1 <= nums1[i], nums2[j] <= 105
- Both
nums1
andnums2
are non-increasing.
import bisect
class Solution:
def maxDistance(self, nums1: List[int], nums2: List[int]) -> int:
ret = 0
for i in range(len(nums1)):
j = bisect.bisect_right(
nums2, False, key=lambda x: x < nums1[i]) - 1
ret = max(ret, j - i)
return ret