You are given a strictly increasing integer array rungs
that represents the height of rungs on a ladder. You are currently on the floor at height 0
, and you want to reach the last rung.
You are also given an integer dist
. You can only climb to the next highest rung if the distance between where you are currently at (the floor or on a rung) and the next rung is at most dist
. You are able to insert rungs at any positive integer height if a rung is not already there.
Return the minimum number of rungs that must be added to the ladder in order for you to climb to the last rung.
Input: rungs = [1,3,5,10], dist = 2 Output: 2 Explanation: You currently cannot reach the last rung. Add rungs at heights 7 and 8 to climb this ladder. The ladder will now have rungs at [1,3,5,7,8,10].
Input: rungs = [3,6,8,10], dist = 3 Output: 0 Explanation: This ladder can be climbed without adding additional rungs.
Input: rungs = [3,4,6,7], dist = 2 Output: 1 Explanation: You currently cannot reach the first rung from the ground. Add a rung at height 1 to climb this ladder. The ladder will now have rungs at [1,3,4,6,7].
1 <= rungs.length <= 105
1 <= rungs[i] <= 109
1 <= dist <= 109
rungs
is strictly increasing.
impl Solution {
pub fn add_rungs(rungs: Vec<i32>, dist: i32) -> i32 {
let mut height = 0;
let mut ret = 0;
for rung in rungs {
if rung - height > dist {
ret += (rung - height - 1) / dist;
}
height = rung;
}
ret
}
}