Given an integer array nums
, return the greatest common divisor of the smallest number and largest number in nums
.
The greatest common divisor of two numbers is the largest positive integer that evenly divides both numbers.
Input: nums = [2,5,6,9,10] Output: 2 Explanation: The smallest number in nums is 2. The largest number in nums is 10. The greatest common divisor of 2 and 10 is 2.
Input: nums = [7,5,6,8,3] Output: 1 Explanation: The smallest number in nums is 3. The largest number in nums is 8. The greatest common divisor of 3 and 8 is 1.
Input: nums = [3,3] Output: 3 Explanation: The smallest number in nums is 3. The largest number in nums is 3. The greatest common divisor of 3 and 3 is 3.
2 <= nums.length <= 1000
1 <= nums[i] <= 1000
class Solution:
def findGCD(self, nums: List[int]) -> int:
return gcd(min(nums), max(nums))
# @param {Integer[]} nums
# @return {Integer}
def find_gcd(nums)
nums.min.gcd(nums.max)
end