You are given a 0-indexed string expression
of the form "<num1>+<num2>"
where <num1>
and <num2>
represent positive integers.
Add a pair of parentheses to expression
such that after the addition of parentheses, expression
is a valid mathematical expression and evaluates to the smallest possible value. The left parenthesis must be added to the left of '+'
and the right parenthesis must be added to the right of '+'
.
Return expression
after adding a pair of parentheses such that expression
evaluates to the smallest possible value. If there are multiple answers that yield the same result, return any of them.
The input has been generated such that the original value of expression
, and the value of expression
after adding any pair of parentheses that meets the requirements fits within a signed 32-bit integer.
Input: expression = "247+38" Output: "2(47+38)" Explanation: The expression evaluates to 2 * (47 + 38) = 2 * 85 = 170. Note that "2(4)7+38" is invalid because the right parenthesis must be to the right of the '+'. It can be shown that 170 is the smallest possible value.
Input: expression = "12+34" Output: "1(2+3)4" Explanation: The expression evaluates to 1 * (2 + 3) * 4 = 1 * 5 * 4 = 20.
Input: expression = "999+999" Output: "(999+999)" Explanation: The expression evaluates to 999 + 999 = 1998.
3 <= expression.length <= 10
expression
consists of digits from'1'
to'9'
and'+'
.expression
starts and ends with digits.expression
contains exactly one'+'
.- The original value of
expression
, and the value ofexpression
after adding any pair of parentheses that meets the requirements fits within a signed 32-bit integer.
class Solution:
def minimizeResult(self, expression: str) -> str:
m = expression.find("+")
smallest = float("inf")
ret = ""
for l in range(m):
for r in range(m + 2, len(expression) + 1):
x = int(expression[l:m]) + int(expression[m + 1:r])
if l > 0:
x *= int(expression[:l])
if r < len(expression):
x *= int(expression[r:])
if x < smallest:
smallest = x
ret = expression[:l] + \
"(" + expression[l:r] + ")" + expression[r:]
return ret