README.md

2278. Percentage of Letter in String

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

Constraints:

• 1 <= s.length <= 100
• s consists of lowercase English letters.
• letter is a lowercase English letter.

Solutions (Rust)

1. Solution

impl Solution {
    pub fn percentage_letter(s: String, letter: char) -> i32 {
        (s.chars().filter(|&c| c == letter).count() * 100 / s.len()) as i32
    }
}