P04_CONFLIP.py

# In this game the player will use N coins numbered from 1 to N, and all the coins will be facing in
# "Same direction" (Either Head or Tail),which will be decided by the player before starting of the game.
#
# The player needs to play N rounds.In the k-th round the player will flip the face of the all coins whose
# number is less than or equal to k. That is, the face of coin i will be reversed, from Head to Tail, or,
# from Tail to Head, for i ≤ k.
#
# Elephant needs to guess the total number of coins showing a particular face after playing N rounds.
# Elephant really becomes quite fond of this game COIN FLIP, so Elephant plays G times. Please help the
# Elephant to find out the answer.
#
# Input
# The first line of input contains an integer T, denoting the number of test cases.
# Then T test cases follow.
#
# The first line of each test contains an integer G, denoting the number of games played by Elephant.
# Each of the following G lines denotes a single game, and contains 3 space separeted integers I, N, Q,
# where I denotes the initial state of the coins, N denotes the number of coins and rounds, and Q, which
# is either 1, or 2 as explained below.
#
# Here I=1 means all coins are showing Head in the start of the game, and I=2 means all coins are showing
# Tail in the start of the game. Q=1 means Elephant needs to guess the total number of coins showing Head
# in the end of the game, and Q=2 means Elephant needs to guess the total number of coins showing Tail in
# the end of the game.
#
# Output
# For each game, output one integer denoting the total number of coins showing the particular face in the
# end of the game.
#
# Constraints
# 1 ≤ T ≤ 10
# 1 ≤ G ≤ 20000
# 1 ≤ N ≤ 109
# 1 ≤ I ≤ 2
# 1 ≤ Q ≤ 2
# Example
#
# Input:
# 1
# 2
# 1 5 1
# 1 5 2
#
# Output:
# 2
# 3

# MY SOLUTION:
testCases = int(input())
while testCases:
    testCases -= 1
    G = int(input())
    while G:
        G -= 1
        I, N, Q = map(int, input().split())
        if N % 2 == 0:
            print(N // 2)
        else:
            if I == Q:
                print(N // 2)
            else:
                print((N // 2) + 1)