Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 8
Total runs: 10
Success rate: 80%
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(5) == [1, 2, 6, 24, 15]
"""
The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(5) == [1, 2, 6, 24, 15]
"""ret = []
for i in range(1,n+1):
if i%2 == 0:
x = 1
for j in range(1,i+1): x *= j
ret += [x]
else:
x = 0
for j in range(1,i+1): x += j
ret += [x]
return ret
def check(candidate):
assert candidate(5) == [1, 2, 6, 24, 15]
assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]
assert candidate(1) == [1]
assert candidate(3) == [1, 2, 6]
Start time: 2023-09-01 02:46:56
Duration: 5.19s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 02:49:56
Duration: 17.05s
Result: Fail
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(5) == [1, 2, 6, 24, 15]
"""
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(i * (i-1))
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 02:52:53
Duration: 4.52s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 02:55:48
Duration: 5.12s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 02:58:46
Duration: 5.17s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 03:01:49
Duration: 15.17s
Result: Fail
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(5) == [1, 2, 6, 24, 15]
"""
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(factorial(i))
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 03:04:50
Duration: 5.48s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 03:07:54
Duration: 5.27s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 03:10:49
Duration: 5.34s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result
Start time: 2023-09-01 03:13:48
Duration: 6.03s
Result: Pass
def f(n):
result = []
for i in range(1, n+1):
if i % 2 == 0:
result.append(1)
for j in range(2, i+1):
result[-1] *= j
else:
result.append(sum(range(1, i+1)))
return result