100.md

Results of GPT-4 on HumanEval/100

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 158

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """return [n + 2*i for i in range(n)]

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate(3) == [3, 5, 7], "Test 3"
    assert candidate(4) == [4,6,8,10], "Test 4"
    assert candidate(5) == [5, 7, 9, 11, 13]
    assert candidate(6) == [6, 8, 10, 12, 14, 16]
    assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"

Runs

✅ Run 1

Start time: 2023-07-18 18:15:59
Duration: 16.25s
Completion tokens: 189
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    stones = [n]
    for i in range(1, n):
        if n % 2 == 0:
            stones.append(stones[i-1] + 2)
        else:
            stones.append(stones[i-1] + 2)
    return stones

✅ Run 2

Start time: 2023-07-18 18:15:45
Duration: 13.84s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 3

Start time: 2023-07-18 18:15:26
Duration: 19.25s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 4

Start time: 2023-07-18 18:15:05
Duration: 20.72s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 5

Start time: 2023-07-18 18:14:47
Duration: 18.22s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 6

Start time: 2023-07-18 18:14:29
Duration: 17.57s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 7

Start time: 2023-07-18 18:14:10
Duration: 18.71s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    stones = [n]
    for i in range(1, n):
        if stones[i-1] % 2 == 0:
            stones.append(stones[i-1] + 2)
        else:
            stones.append(stones[i-1] + 2)
    return stones

✅ Run 8

Start time: 2023-07-18 18:13:53
Duration: 17.47s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 9

Start time: 2023-07-18 18:13:39
Duration: 13.67s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile

✅ Run 10

Start time: 2023-07-18 18:13:17
Duration: 21.78s
Completion tokens: 193
Result: Pass

def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    pile = [n]
    for i in range(1, n):
        if pile[i-1] % 2 == 0:
            pile.append(pile[i-1] + 2)
        else:
            pile.append(pile[i-1] + 2)
    return pile