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Results of GPT-4 on HumanEval/69

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 191

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''frq = [0] * (max(lst) + 1)
    for i in lst:
        frq[i] += 1;

    ans = -1
    for i in range(1, len(frq)):
        if frq[i] >= i:
            ans = i
    
    return ans

Unit tests

def check(candidate):

    # manually generated tests
    assert candidate([5, 5, 5, 5, 1]) == 1
    assert candidate([4, 1, 4, 1, 4, 4]) == 4
    assert candidate([3, 3]) == -1
    assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8
    assert candidate([2, 3, 3, 2, 2]) == 2

    # automatically generated tests
    assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1
    assert candidate([3, 2, 8, 2]) == 2
    assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1
    assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1
    assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1
    assert candidate([1, 9, 10, 1, 3]) == 1
    assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5
    assert candidate([1]) == 1
    assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4
    assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2
    assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1
    assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4
    assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4
    assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2
    assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1
    assert candidate([10]) == -1
    assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2
    assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1
    assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1
    assert candidate([3, 10, 10, 9, 2]) == -1

Runs

✅ Run 1

Start time: 2023-07-18 18:29:44
Duration: 22.28s
Completion tokens: 206
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    res = -1
    for num in count:
        if num <= count[num]:
            res = max(res, num)
    return res

✅ Run 2

Start time: 2023-07-18 18:29:25
Duration: 18.93s
Completion tokens: 208
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    result = -1
    for key, value in count.items():
        if key <= value:
            result = max(result, key)
    return result

✅ Run 3

Start time: 2023-07-18 18:29:01
Duration: 24.44s
Completion tokens: 304
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    # Create a dictionary to store the frequency of each integer
    freq = {}
    for i in lst:
        if i in freq:
            freq[i] += 1
        else:
            freq[i] = 1

    # Sort the dictionary by key in descending order
    sorted_freq = sorted(freq.items(), key=lambda x: x[0], reverse=True)

    # Iterate over the sorted dictionary
    for key, value in sorted_freq:
        # If the frequency is greater than or equal to the integer itself, return the integer
        if value >= key:
            return key

    # If no such value exists, return -1
    return -1

✅ Run 4

Start time: 2023-07-18 18:28:41
Duration: 19.44s
Completion tokens: 297
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    # Create a dictionary to store the frequency of each number
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1

    # Initialize the result as -1
    result = -1

    # Iterate over the frequency dictionary
    for num, freq in freq_dict.items():
        # Check if the frequency is greater than or equal to the number
        if freq >= num:
            # Update the result if the current number is greater than the current result
            result = max(result, num)

    return result

✅ Run 5

Start time: 2023-07-18 18:28:23
Duration: 17.46s
Completion tokens: 208
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    result = -1
    for key in count:
        if key <= count[key] and key > result:
            result = key
    return result

✅ Run 6

Start time: 2023-07-18 18:28:04
Duration: 18.94s
Completion tokens: 208
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    result = -1
    for key in count:
        if key <= count[key] and key > result:
            result = key
    return result

✅ Run 7

Start time: 2023-07-18 18:27:49
Duration: 15.21s
Completion tokens: 206
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    result = -1
    for num in count:
        if num <= count[num]:
            result = max(result, num)
    return result

✅ Run 8

Start time: 2023-07-18 18:27:31
Duration: 17.93s
Completion tokens: 205
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    valid_numbers = [num for num in count if count[num] >= num]
    return max(valid_numbers) if valid_numbers else -1

✅ Run 9

Start time: 2023-07-18 18:27:14
Duration: 17.1s
Completion tokens: 208
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    from collections import Counter
    count = Counter(lst)
    result = -1
    for num in count:
        if num <= count[num] and num > result:
            result = num
    return result

✅ Run 10

Start time: 2023-07-18 18:26:56
Duration: 18.11s
Completion tokens: 236
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    frequency = {}
    for i in lst:
        if i in frequency:
            frequency[i] += 1
        else:
            frequency[i] = 1
    max_val = -1
    for key, value in frequency.items():
        if key <= value and key > max_val:
            max_val = key
    return max_val