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surrounded-regions.js
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surrounded-regions.js
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/**
* Surrounded Regions
*
* Given a 2D board containing 'X' and 'O' (the letter O), capture all regions surrounded by 'X'.
*
* A region is captured by flipping all 'O's into 'X's in that surrounded region.
*
* Example:
*
* X X X X
* X O O X
* X X O X
* X O X X
* After running your function, the board should be:
*
* X X X X
* X X X X
* X X X X
* X O X X
* Explanation:
*
* Surrounded regions shouldn’t be on the border, which means that any 'O' on the border of the board are
* not flipped to 'X'. Any 'O' that is not on the border and it is not connected to an 'O' on the border
* will be flipped to 'X'. Two cells are connected if they are adjacent cells connected horizontally or vertically.
*/
const dx = [-1, 1, 0, 0];
const dy = [0, 0, -1, 1];
/**
* @param {character[][]} board
* @return {void} Do not return anything, modify board in-place instead.
*/
const solve = board => {
if (!board || board.length === 0 || board[0].length === 0) return;
const n = board.length;
const m = board[0].length;
// scan the borders and mark the 'O's to '1'
for (let i = 0; i < n; i++) {
for (let j = 0; j < m; j++) {
if ((i === 0 || i === n - 1 || j === 0 || j === m - 1) && board[i][j] === 'O') {
bfs(board, n, m, i, j);
}
}
}
// scan the inner area and mark the 'O's to 'X'
for (let i = 1; i < n; i++) {
for (let j = 1; j < m; j++) {
if (board[i][j] === 'O') {
board[i][j] = 'X';
}
}
}
// reset all the '1's to 'O's
for (let i = 0; i < n; i++) {
for (let j = 0; j < m; j++) {
if (board[i][j] === '1') {
board[i][j] = 'O';
}
}
}
};
const bfs = (board, n, m, i, j) => {
const queue = [];
queue.push([i, j]);
board[i][j] = '1';
while (queue.length > 0) {
const pos = queue.shift();
for (let k = 0; k < 4; k++) {
i = pos[0] + dx[k];
j = pos[1] + dy[k];
if (i >= 0 && i < n && j >= 0 && j < m && board[i][j] === 'O') {
board[i][j] = '1';
queue.push([i, j]);
}
}
}
};
export { solve };