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longest_palindrome_substring.js
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/**
* @param {string} s
* @return {string}
*/
/* function longestPalindrome(s) {
const palindrome = (x) => x.split("").reverse().join("") === x;
if (s.length == 1) {
return s;
}
if (s.length == 2) {
return s[0] == s[s.length - 1] ? s : s[0];
}
let finalList = [];
for (let i = 0; i < s.length; i++) {
let pointEnd = s.length;
while (pointEnd > i) {
let currentStr = s.substring(i, pointEnd);
if (
currentStr[0] == currentStr[currentStr.length - 1] &&
palindrome(currentStr) &&
currentStr.length > 1
) {
finalList.push(currentStr);
}
pointEnd--;
}
}
return finalList.sort((a, b) => b.length - a.length)[0];
} */
/**
* @param {string} s
* @return {string}
*/
var longestPalindrome = function (s) {
let longest = "";
const palindrome = (i, j) => {
while (i >= 0 && j < s.length && s[i] === s[j]) {
console.log(i, " ", j);
i--;
j++;
}
console.log(i, ":", j);
return s.substring(i + 1, j);
};
for (let i = 0; i < s.length; i++) {
const odd = palindrome(i, i);
const even = palindrome(i, i + 1);
const currLongest = odd.length > even.length ? odd : even;
longest = longest.length > currLongest.length ? longest : currLongest;
}
return longest;
};
/**
* @param {string} s
* @return {string}
*/
function longestPalindrome(s) {
let start = 0;
let end = 0;
for (let i = 0; i < s.length; i++) {
let len1 = expandAroundCenter(s, i, i);
let len2 = expandAroundCenter(s, i, i + 1);
let length = Math.max(len1, len2);
if (length > end - start) {
start = i - Math.floor((length - 1) / 2);
end = i + Math.floor(length / 2);
}
}
return s.slice(start, end + 1);
}
function expandAroundCenter(s, left, right) {
while (left >= 0 && right < s.length && s[left] === s[right]) {
left--;
right++;
}
return right - left - 1;
}
function longestPalindrome(s) {
var T = "#".concat(s.split("").join("#"), "#");
var P = new Array(T.length).fill(0);
var C = 0;
var R = 0;
var maxLen = 0;
var maxI = 0;
for (var i = 0; i < T.length; i++) {
if (i < R) {
P[i] = Math.min(R - i, P[2 * C - i]);
} else {
P[i] = 0;
}
while (
i - P[i] >= 0 &&
i + P[i] < T.length &&
T[i - P[i] - 1] == T[i + P[i] + 1]
) {
P[i]++;
}
if (i + P[i] > R) {
C = i;
R = i + P[i];
}
if (P[i] > maxLen) {
maxLen = P[i];
maxI = i;
}
}
var result = s.substring((maxI - maxLen) / 2, (maxI - maxLen) / 2 + maxLen);
return result;
}
console.log(longestPalindrome("acacaada"));