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Unable to cancel
a luv_work_ctx_t
handle
#630
Comments
Little bit of diving into the libuv docs, I dug up this tidbit
However, when modifying the above code to try and use
Note, updated code local luv = require("luv")
local work_fn = function()
local count = 0
while count > 0 do
count = count + 1
end
return
end
local after_work_fn = function()
print("Work Complete!")
end
local work = luv.new_work(work_fn, after_work_fn)
work:queue()
local timer = luv.new_timer()
timer:start(100, 0, function()
luv.cancel(work)
end) Digging deeper still, the cancel doc actually says
If I am reading that correctly, does that mean that you can't cancel a
|
I'm not too familiar with the
|
My C skills are quite dull, but I could see if I can get that implemented. It will likely take me alot longer than someone with more intimate knowledge with the luv codebase though. I do agree with your reaction. I spent a bit of time digging through the source to see if there was a way to convince lua to cancel the That said, this is something that will prevent my work going forward so I am willing to put some (hopefully guided) effort into rectifying this, and maybe sharpening my C skills in the process lol. |
EDIT: Ignore this, see comment below In looking at it a bit more, I think this might be a more involved change than I was initially thinking it would be. local work = luv.new_work(work_fn, after_work_fn)
work:queue()
-- the 'work' userdata doesn't have any reference to the uv_work_t created during 'queue()',
-- so there's no way to implement 'cancel()' which needs a uv_work_t
work:cancel() I think a complete solution will involve returning a A quicker fix might be to add a |
Actually, I think the right solution might be to make In that case, the fix would be to make From the Lua side of things, usage would look something like: local work = luv.new_work(work_fn, after_work_fn)
local foo = work:queue()
foo:cancel() |
I took a bit of a deeper peek under the hood last night after I saw your comments, and while I agree with the latter opinion (of I can read the code generally fine but I am failing to grasp how the lua pieces of this interact with the c code under the hood (due to my not knowing how lua is implemented within C in general). I am going to step back on this and follow along the chain, but I don't believe I'll have any useful code I can provide here |
No worries, I've started attempting an implementation in my fork here: https://github.com/squeek502/luv/tree/cancelable-work |
When testing things I realized that the example in the first comment in this thread won't work even if
Further, local luv = require("luv")
local work_fn = function(i)
print(i)
return i
end
local after_work_fn = function(...)
print("after_work_fn", ...)
end
local work = luv.new_work(work_fn, after_work_fn)
-- queue 16 instances
local reqs = {}
for i=1,16 do
table.insert(reqs, work:queue(i))
end
-- cancel them all
for i, queued in ipairs(reqs) do
print(i, queued:cancel())
end
-- now run the loop
luv.run() Will output something like (the added comments are annotations to make it more understandable): -- the first four queued can't be canceled
1 nil EBUSY: resource busy or locked EBUSY
2 nil EBUSY: resource busy or locked EBUSY
3 nil EBUSY: resource busy or locked EBUSY
4 nil EBUSY: resource busy or locked EBUSY
-- the rest are successfully canceled
5 0
6 0
7 0
8 0
9 0
10 0
11 0
12 0
13 0
14 0
15 0
16 0
after_work_fn -- these are all the canceled `uv_work_t`
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn
after_work_fn -- end successfully canceled `uv_work_t`
2 -- this is work_fn being called for the 2nd queued work
after_work_fn 2
3 -- this is work_fn being called for the 3rd queued work
1 -- this is work_fn being called for the 1st queued work
after_work_fn 3
after_work_fn 1
4 -- this is work_fn being called for the 4th queued work
after_work_fn 4 So, your use case unfortunately doesn't seem to fit this API. |
Well thats no good :( What is the recommended way to handle something like my initial use case (work that needs to be stopped "mid flight")? |
Libuv is an event loop, while it's running your code it has no control. |
That doesn't make sense. Libuv is an event loop, any subprocess it starts should be terminable (even if it is forcible). That said it does appear that the thread doc states the following
So that brings me back to my initial request then. How do I |
Libuv is not preemptive, libuv is never in control when user code is running. The paragraph immediately preceding that documentation notes the limitation:
You can cancel work requests that have not yet begun, but once the request has started it must run to completion. Libuv runs work requests by calling the work function, at which point the only way it regains control is when that function returns. |
To be clear then, this means there is no way to kill an in flight I am not completely set on using the work context for this, it just seemed to be the best fit for what I needed. I believe luv also offers true OS threads though that seemed much more expensive for what I am looking for (my framework I am building cannot make guarantees about the work being done and needs a way to kill (at a user's request) active running work). I want to be clear, I am not against using an alternative. I am asking what that alternative may be if using |
It's not all that uncommon, stopping an in-flight work request requires preempting, which is quite difficult to do (nearly impossible at Libuv's level). As far as I'm aware Libuv doesn't provide any way to stop, kill, or otherwise halt a spawned thread; much less do the same for an individual work request (which will be running on one of Libuv's threadpool threads). If you cannot guarantee that the work will ever finish, you'll either need to delegate it to its own thread (at which point the os scheduler will handle it behaving poorly) or instrument it with your own code that will preempt it if it runs for too long or something similar. For the latter, you can use |
Well that's not the answer I was hoping for lol. I appreciate the direction. It appears that the request to get |
Leave it open, we definitely should make our |
luv_work_ctx_t
handle?cancel
a luv_work_ctx_t
handle
RE: #629
If you create new work via the
uv.new_work
function and then queue it with thequeue_work
function, how do you go about "killing" said work?Some example code to show what I mean
As we see in the above code,
work_fn
will never "exit" and thus run infinitely. I don't see anything in the docs about how to stop "rogue" work processes. Of course, one isn't going to intentionally create code that will run forever, but it is certainly possible that code could end up doing so. For my use case, I am looking more from the angle of "code is running too long and user wants it to stop". I don't see how I would go about doing that.Am I missing something?
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