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singlylinkedlist.go
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/
singlylinkedlist.go
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package linkedlist
// demonstration of singly linked list in golang
import (
"errors"
"fmt"
)
// Singly structure with length of the list and its head
type Singly struct {
length int
// Note that Node here holds both Next and Prev Node
// however only the Next node is used in Singly methods.
Head *Node
}
// NewSingly returns a new instance of a linked list
func NewSingly() *Singly {
return &Singly{}
}
// AddAtBeg adds a new snode with given value at the beginning of the list.
func (ll *Singly) AddAtBeg(val interface{}) {
n := NewNode(val)
n.Next = ll.Head
ll.Head = n
ll.length++
}
// AddAtEnd adds a new snode with given value at the end of the list.
func (ll *Singly) AddAtEnd(val interface{}) {
n := NewNode(val)
if ll.Head == nil {
ll.Head = n
ll.length++
return
}
cur := ll.Head
for ; cur.Next != nil; cur = cur.Next {
}
cur.Next = n
ll.length++
}
// DelAtBeg deletes the snode at the head(beginning) of the list and returns its value. Returns -1 if the list is empty.
func (ll *Singly) DelAtBeg() interface{} {
if ll.Head == nil {
return -1
}
cur := ll.Head
ll.Head = cur.Next
ll.length--
return cur.Val
}
// DelAtEnd deletes the snode at the tail(end) of the list and returns its value. Returns -1 if the list is empty.
func (ll *Singly) DelAtEnd() interface{} {
if ll.Head == nil {
return -1
}
if ll.Head.Next == nil {
return ll.DelAtBeg()
}
cur := ll.Head
for ; cur.Next.Next != nil; cur = cur.Next {
}
retval := cur.Next.Val
cur.Next = nil
ll.length--
return retval
}
// Count returns the current size of the list.
func (ll *Singly) Count() int {
return ll.length
}
// Reverse reverses the list.
func (ll *Singly) Reverse() {
var prev, Next *Node
cur := ll.Head
for cur != nil {
Next = cur.Next
cur.Next = prev
prev = cur
cur = Next
}
ll.Head = prev
}
// ReversePartition Reverse the linked list from the ath to the bth node
func (ll *Singly) ReversePartition(left, right int) error {
err := ll.CheckRangeFromIndex(left, right)
if err != nil {
return err
}
tmpNode := NewNode(-1)
tmpNode.Next = ll.Head
pre := tmpNode
for i := 0; i < left-1; i++ {
pre = pre.Next
}
cur := pre.Next
for i := 0; i < right-left; i++ {
next := cur.Next
cur.Next = next.Next
next.Next = pre.Next
pre.Next = next
}
ll.Head = tmpNode.Next
return nil
}
func (ll *Singly) CheckRangeFromIndex(left, right int) error {
if left > right {
return errors.New("left boundary must smaller than right")
} else if left < 1 {
return errors.New("left boundary starts from the first node")
} else if right > ll.length {
return errors.New("right boundary cannot be greater than the length of the linked list")
}
return nil
}
// Display prints out the elements of the list.
func (ll *Singly) Display() {
for cur := ll.Head; cur != nil; cur = cur.Next {
fmt.Print(cur.Val, " ")
}
fmt.Print("\n")
}