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Copy path100.相同的树.java
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100.相同的树.java
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import java.util.ArrayList;
import java.util.function.Predicate;
/*
* @lc app=leetcode.cn id=100 lang=java
*
* [100] 相同的树
*
* https://leetcode-cn.com/problems/same-tree/description/
*
* algorithms
* Easy (56.05%)
* Likes: 298
* Dislikes: 0
* Total Accepted: 57.6K
* Total Submissions: 102.8K
* Testcase Example: '[1,2,3]\n[1,2,3]'
*
* 给定两个二叉树,编写一个函数来检验它们是否相同。
*
* 如果两个树在结构上相同,并且节点具有相同的值,则认为它们是相同的。
*
* 示例 1:
*
* 输入: 1 1
* / \ / \
* 2 3 2 3
*
* [1,2,3], [1,2,3]
*
* 输出: true
*
* 示例 2:
*
* 输入: 1 1
* / \
* 2 2
*
* [1,2], [1,null,2]
*
* 输出: false
*
*
* 示例 3:
*
* 输入: 1 1
* / \ / \
* 2 1 1 2
*
* [1,2,1], [1,1,2]
*
* 输出: false
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
/**
* 个人垃圾解法 用作反省
* class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if(p == null && q == null) return true;
if(p == null || q == null) return false;
ArrayList<Integer> firstArray = new ArrayList<Integer>();
ArrayList<Integer> secondArray = new ArrayList<Integer>();
fillArrayList(p, firstArray);
fillArrayList(q, secondArray);
if(firstArray.size() != secondArray.size()) {
System.out.println(firstArray.size() + " "+ secondArray.size());
return false;
}
Boolean result = true;
for (int i = 0; i < firstArray.size(); i++) {
if(secondArray.get(i) == null && firstArray.get(i) == null) {
continue;
}
if(secondArray.get(i) == null || firstArray.get(i) == null) {
return false;
}
if(firstArray.get(i).compareTo(secondArray.get(i)) != 0) {
System.out.println(firstArray.get(i) + " != " + secondArray.get(i));
return false;
}
}
return result;
}
public void fillArrayList(TreeNode root, ArrayList array ) {
if(root == null) {
array.add(null);
return;
}
array.add(root.val);
fillArrayList(root.left, array);
fillArrayList(root.right, array);
}
}
*/
class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if(p == null && q == null) return true;
if(p == null || q == null) return false;
return p.val == q.val && isSameTree(p.left, q.left) &&
isSameTree(p.right, q.right);
}
}
// @lc code=end