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❓ [QUESTION] About parity in irreducible representation #246

Answered by Linux-cpp-lisp
hyuntae-cho asked this question in Q&A
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Hi @choant ,

This is almost correct--- the key is that the parity in the irrep does not describe the sign of the data itself, but rather how that sign should transform under inversions. The L=1 spherical harmonic, for example, is a vector and thus has odd parity (-1); this means that when you invert the input coordinates the sign of the L=1 tensor flips. What parity -1 in the irrep signifies is that this flip occurs, not the current "state" of the sign for some particular data that transforms according to the irrep.

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Converted from issue

This discussion was converted from issue #237 on September 13, 2022 03:37.