forked from TheAlgorithms/Python
-
Notifications
You must be signed in to change notification settings - Fork 0
/
double_sort.py
44 lines (40 loc) · 1.8 KB
/
double_sort.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
from typing import Any
def double_sort(collection: list[Any]) -> list[Any]:
"""This sorting algorithm sorts an array using the principle of bubble sort,
but does it both from left to right and right to left.
Hence, it's called "Double sort"
:param collection: mutable ordered sequence of elements
:return: the same collection in ascending order
Examples:
>>> double_sort([-1 ,-2 ,-3 ,-4 ,-5 ,-6 ,-7])
[-7, -6, -5, -4, -3, -2, -1]
>>> double_sort([])
[]
>>> double_sort([-1 ,-2 ,-3 ,-4 ,-5 ,-6])
[-6, -5, -4, -3, -2, -1]
>>> double_sort([-3, 10, 16, -42, 29]) == sorted([-3, 10, 16, -42, 29])
True
"""
no_of_elements = len(collection)
for _ in range(
int(((no_of_elements - 1) / 2) + 1)
): # we don't need to traverse to end of list as
for j in range(no_of_elements - 1):
# apply the bubble sort algorithm from left to right (or forwards)
if collection[j + 1] < collection[j]:
collection[j], collection[j + 1] = collection[j + 1], collection[j]
# apply the bubble sort algorithm from right to left (or backwards)
if collection[no_of_elements - 1 - j] < collection[no_of_elements - 2 - j]:
(
collection[no_of_elements - 1 - j],
collection[no_of_elements - 2 - j],
) = (
collection[no_of_elements - 2 - j],
collection[no_of_elements - 1 - j],
)
return collection
if __name__ == "__main__":
# allow the user to input the elements of the list on one line
unsorted = [int(x) for x in input("Enter the list to be sorted: ").split() if x]
print("the sorted list is")
print(f"{double_sort(unsorted) = }")