diff --git a/1313/README.md b/1313/README.md new file mode 100644 index 0000000..1640609 --- /dev/null +++ b/1313/README.md @@ -0,0 +1,26 @@ +We are given a list nums of integers representing a list compressed with run-length encoding. + +Consider each adjacent pair of elements [freq, val] = [nums[2*i], nums[2*i+1]] (with i >= 0). For each such pair, there are freq elements with value val concatenated in a sublist. Concatenate all the sublists from left to right to generate the decompressed list. + +Return the decompressed list. + + + +Example 1: + +Input: nums = [1,2,3,4] +Output: [2,4,4,4] +Explanation: The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2]. +The second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4]. +At the end the concatenation [2] + [4,4,4] is [2,4,4,4]. +Example 2: + +Input: nums = [1,1,2,3] +Output: [1,3,3] + + +Constraints: + +2 <= nums.length <= 100 +nums.length % 2 == 0 +1 <= nums[i] <= 100 \ No newline at end of file diff --git a/1313/Solution.py b/1313/Solution.py new file mode 100644 index 0000000..bb5cb67 --- /dev/null +++ b/1313/Solution.py @@ -0,0 +1,14 @@ +class Solution: + def decompressRLElist(self, nums: List[int]) -> List[int]: + remainingList = nums + output = [] + while remainingList: + if len(remainingList) >= 2: + frequency = remainingList[0] + value = remainingList[1] + remainingList = remainingList[2:] + + for i in range(frequency): + output.append(value) + + return output \ No newline at end of file