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Copy pathDSA_LAB_SESSIONAL.c
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DSA_LAB_SESSIONAL.c
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/*Develop a calculator program for infix arithmetic expressions. For example, given the expression 5 ∗ (((9 + 8) ∗ (4 ∗ 6)) + 7),
the function outputs the result 2075. Hint: Convert the infix expression to postfix expression, then evaluate.
NOTE:
The code must be properly commented, so that any end user can easily understand. [2 marks]
The input may be any arithmetic expression. Your function should read the expression from standard input,
perform the computation and output the result.
[5 marks]
Your program must check whether the given expression is valid or not. Some examples of invalid expressions are:
((2+3), (2+3)), 2+3*, 2--, ++5, 3/0 etc.
[3 marks]
*/
// Header files
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <math.h>
#define MAX 50 // defining max=50
char infix[MAX]; // to store infix expression
char postfix[MAX]; // to store postfix
int stack[MAX];
int top;
// function to check invalid input
int check()
{
char prev, symbol;
for (int i = 0; i < strlen(infix); i++)
{
if (i > 0)
prev = infix[i - 1];
symbol = infix[i];
if (symbol == ',')
return 0;
else if (symbol == '+' && prev == '+')
return 0;
else if (symbol == '-' && prev == '-')
return 0;
else if (symbol == '0' && prev == '/')
return 0;
}
return 1;
}
int isempty() // to check if the stack is empty or not
{
if (top == -1)
return 1;
else
return 0;
}
void push(int symbol)
{
if (top > MAX)
{
printf("STACK OVERFLOW!\n");
exit(1);
}
stack[++top] = symbol;
}
int pop()
{
if (isempty())
{
printf("STACK OVERFLOW!\n");
exit(1);
}
return (stack[top--]);
}
// function to check precedence
int priority(char symbol)
{
switch (symbol)
{
case '(':
return 0;
case '+':
case '-':
return 1;
case '*':
case '/':
case '%':
return 2;
case '^':
return 3;
default:
return 0;
}
}
int eval_post()
{
int a, b, temp, result, i; // a to store top element,b to store next to top element,temp to store result,result to store the FINAL ANSWER
for (int i = 0; i < strlen(postfix); i++)
{
if (postfix[i] <= '9' && postfix[i] >= '0')
push(postfix[i] - '0');
else
{
a = pop(); // stores top value
b = pop(); // stores top-1 value
switch (postfix[i])
{
case '+':
temp = b + a;
break;
case '-':
temp = b - a;
break;
case '*':
temp = b * a;
break;
case '/':
temp = b / a;
break;
case '%':
temp = b % a;
break;
case '^':
temp = pow(b, a);
break;
}
push(temp); // inserting it in the stack
}
}
result = pop();
return (result);
}
void infix_to_postfix()
{
int i, p = 0;
char next, symbol;
for (int i = 0; i < strlen(infix); i++)
{
symbol = infix[i];
switch (symbol)
{
case '(':
push(symbol);
break;
case ')':
while ((next = pop()) != '(')
postfix[p++] = next;
break;
case '+':
case '-':
case '*':
case '/':
case '%':
case '^':
while (!isempty() && priority(stack[top]) >= priority(symbol))
postfix[p++] = pop();
push(symbol);
break;
default:
postfix[p++] = symbol;
}
}
while (!isempty())
postfix[p++] = pop();
postfix[p] = '\0';
}
void main()
{
top = -1;
int value; // to store the evaluated value of postfix
printf("Enter the infix statement\n");
gets(infix);
if (check(infix) == 1)
{
infix_to_postfix();
printf("Postfix:\n");
printf("%s\n", postfix);
value = eval_post();
printf("Value of the postfix expression is %d", value);
}
else
{
printf("Invalid Input!Please try again \n");
}
}