Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

is there a way to group selectors to specify precedence? #101

Open
dreyks opened this issue Apr 13, 2022 · 2 comments
Open

is there a way to group selectors to specify precedence? #101

dreyks opened this issue Apr 13, 2022 · 2 comments

Comments

@dreyks
Copy link

dreyks commented Apr 13, 2022

I'm trying to generate the following xpath string (so that I get the deepest element that contains the text I need)

(//*[contains(normalize-space(string(.)), 'Text')]/@id)[position() = last()]

but

XPath.anywhere[XPath.string.n.contains('Text')].attr(:id)[XPath.position.equals(XPath.last)]

generates

//*[contains(normalize-space(string(.)), 'Text')]/@id[(position() = last())]

which is kinda logical, considering how the XPath gem works in general, but not what I want :)

I've looked through the code and looks like there's no way to add parenthesis to the on in a where expression, but maybe I'm missing something

I can't do the filtering in the ruby-land because this is only a part of my bigger XPath selector so I need it to return only one node

@jnicklas
Copy link
Collaborator

Interesting! I don't think this is currently possible, unfortunately.

@dreyks
Copy link
Author

dreyks commented Apr 13, 2022

yeah, that's what i was afraid of :)

thx for the response

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

No branches or pull requests

2 participants