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48.旋转图像.py
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#
# @lc app=leetcode.cn id=48 lang=python3
#
# [48] 旋转图像
#
# https://leetcode-cn.com/problems/rotate-image/description/
#
# algorithms
# Medium (60.48%)
# Total Accepted: 18.5K
# Total Submissions: 30.7K
# Testcase Example: '[[1,2,3],[4,5,6],[7,8,9]]'
#
# 给定一个 n × n 的二维矩阵表示一个图像。
#
# 将图像顺时针旋转 90 度。
#
# 说明:
#
# 你必须在原地旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要使用另一个矩阵来旋转图像。
#
# 示例 1:
#
# 给定 matrix =
# [
# [1,2,3],
# [4,5,6],
# [7,8,9]
# ],
#
# 原地旋转输入矩阵,使其变为:
# [
# [7,4,1],
# [8,5,2],
# [9,6,3]
# ]
#
#
# 示例 2:
#
# 给定 matrix =
# [
# [ 5, 1, 9,11],
# [ 2, 4, 8,10],
# [13, 3, 6, 7],
# [15,14,12,16]
# ],
#
# 原地旋转输入矩阵,使其变为:
# [
# [15,13, 2, 5],
# [14, 3, 4, 1],
# [12, 6, 8, 9],
# [16, 7,10,11]
# ]
#
#
#主要是认真观察发现可以通过对称和转置来实现旋转,或者通过四个四个进行旋转来实现整体旋转
class Solution:
def rotate(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
col=len(matrix)
row=len(matrix[0])
for tem in range(int(col/2)):
matrix[tem],matrix[col-1-tem]=matrix[col-1-tem],matrix[tem]
for i in range(col):
for j in range(i,row):
matrix[i][j],matrix[j][i]=matrix[j][i],matrix[i][j]