Feature | Function to check if two words are anagrams of each other

strings/strings.go

@@ -0,0 +1,29 @@
+package strings
+
+/**
+	Checks if two strings are perfect anagrams of each other using character count comparison.
+	Anagrams are formed by rearranging the letters of one string using all the original letters exactly once.
+
+	Example: "listen" and "silent" are perfect anagrams of each other, while "now silent" and "listennow" are not.
+**/
+func AreAnagrams(s1, s2 string) bool {
+	// If both strings are of unequal length, they are not anagrams
+	if len(s1) != len(s2) {
+		return false
+	}
+
+	var charCount = make(map[rune]int)
+
+	for _, ch := range s1 {
+		charCount[ch]++
+	}
+
+	for _, ch := range s2 {
+		charCount[ch]--
+		if charCount[ch] < 0 {
+			return false
+		}
+	}
+
+	return true
+}

strings/strings_test.go

@@ -0,0 +1,35 @@
+package strings
+
+import (
+	"fmt"
+	"testing"
+)
+
+func TestAreAnagrams(t *testing.T) {
+	tests := []struct {
+		s1   string
+		s2   string
+		want bool
+	}{
+		{"", "", true},
+		{"a", "a", true},
+		{"aa", "aa", true},
+		{"abcd", "dcba", true},
+		{"anagram", "nag a ram", false},
+		{"listen", "silent", true},
+		{"abcdefg", "gfedcba", true},
+		{"abc", "abcd", false},
+		{"abcd", "dcbb", false},
+		{":-;][=+", "+;=:", false},
+		{":-asds;][=+", "+a;s[-d=:s]", true},
+		{":-asds;][=+", "+;=:", false},
+		{":-;][=+", "+asds;=:", false},
+	}
+	for _, input := range tests {
+		t.Run(fmt.Sprintf("TestAreAnagrams(%v, %v)", input.s1, input.s2), func(t *testing.T) {
+			if got := AreAnagrams(input.s1, input.s2); got != input.want {
+				t.Errorf("AreAnagrams() = %v, want %v", got, input.want)
+			}
+		})
+	}
+}