NW-6 | AREEB-SATTAR | JS1| [TECH ED] Complete week 4 exercises | WEEK-4 #184
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| expect(repeatString("Ali", 0)).toBe(""); | ||
| expect(repeatString("Ali", 1)).toBe("Ali"); | ||
| expect(repeatString("Ali", -2)).toBe("negative count is not valid"); | ||
| }); |
| function countChar(str, char) { | ||
| let index = 0; | ||
| for (let i = 0; i < str.length; i++) { | ||
| if (str[i] === char) { |
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This is a well written code however can you explain this a bit? It seems a bit confusing to me, maybe if I understand what you have done here, it would make sense to me.
| function getOrdinalNumber(num) { | ||
| if (num % 10 === 1) { | ||
| if (num === 11) { | ||
| return "11th"; |
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I did mine a bit differently. Mine is a bit more concise, but this makes sense as well. Well done!
| @@ -1,5 +1,24 @@ | |||
| // implement a function countChar that counts the number of times a character occurs in a string | |||
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| function countChar(str, char) { | |||
| let index = 0; | |||
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Can you think of a more descriptive name for this variable? We already have i which keeps track of the index
| if (str[i] === char) { | ||
| index++; | ||
| } | ||
| while (str[i + 1] === char) { |
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From my understanding, this loop will keep counting up and moving through the string if the next element in the string is the character we're counting. However if we just let the for loop run, it will already check every character in the string. So this while loop isn't doing much for us, just using the for loop will be easier to understand 🙂
| @@ -1,4 +1,18 @@ | |||
| // In this week's prep, we started implementing getOrdinalNumber | |||
| function getOrdinalNumber(num) { | |||
| if (num % 10 === 1) { | |||
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Great use of the modulo % operator Areeb!
| if (num != Math.round(num)) { | ||
| return false; | ||
| } | ||
| for (var i = 2; i < num; i++){ |
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Great spot that you can begin this loop at 2! I would just replace var with let, as this helps to keep the variable scope as small as possible, in this case, only inside the for loop. Otherwise you would be able to access i outside of the loop which could cause bugs.
| if (num === 0) { | ||
| return ""; | ||
| } | ||
| if (num === 1) { | ||
| return str; | ||
| } else return repeatedString; |
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Check what happens when you give str.repeat(..) the number 0 or 1. You might find that you can remove a few if statements from your function 😉
As a general rule of thumb, even if you don't need to repeat the string (if the number is 1, for example), as long as the built-in function still behaves as expected, it's fine to still use its output.
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