Assignment 1

Assignment 1/Karn Tiwari/Question 1

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+List1=['I','S','T','E']
+List2=List1
+List2[0]=’1’
+print(List1)     #['1', 'S', 'T', 'E'] id of list1 and list2 are same object so any change in list2 is reflected in list1
+List1=List1+[]
+List2[1]=2
+print(List1)     #['1', 'S', 'T', 'E'] id of list1 and list2 are now differen object as list1 is concatenated with Null list
+
+#Yes the output is different
+
+List1=['I','S','T','E']
+List2=List1
+List2[0]=’1’
+print(List1)     #['1', 'S', 'T', 'E'] id of list1 and list2 are same object so any change in list2 is reflected in list1
+List1+=[]
+List2[1]=2
+print(List1)     #['1', '2', 'T', 'E'] id of list1 and list2 are same object

Assignment 1/Karn Tiwari/Question 2

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+#Sorting of elements
+arr=[10,9,8,7,6,5,4,3,2,1]
+print(arr)
+d=len(arr)
+for i in range(d):
+    for j in range(i+1,d):
+        if arr[i]>=arr[j]:
+            arr[i],arr[j]=arr[j],arr[i]
+print(arr)
+
+#Binary search Algorithm
+key=5
+ma=d
+mi=0
+y=0
+
+while ma>mi:
+    mid=int((ma+mi)//2)
+    if key==arr[mid]:
+        y=1
+        p=mid+1
+        break
+    elif key>arr[mid]:
+        mi=mid
+    else:
+        ma=mid
+
+if y==1:
+    print("key element found @ ",p)
+else:
+    print("key element not found")

Assignment 1/Karn Tiwari/Question 3

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+l1=[1,2,3]
+l2=[1,2,3]
+print(id(l1)==id(l2))   # False for two list of same element id is different,different object
+
+str1='good'
+str2='good'
+print(id(str1)==id(str2))  # True for same numbers and string id is different,same object
+

Assignment 1/Karn Tiwari/Question 4

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+a=[1,2,3,4,5,6,7,8,9,10]
+a=[i for i in a if ((i**3)%3)==1]     # [1,4,7,10] one line code