Converts a date to the day of the year, determines days left in the year

0x03-debugging/3-print_remaining_days.c

@@ -0,0 +1,37 @@
+#include <stdio.h>
+#include "main.h"
+
+/**
+* print_remaining_days - takes a date and prints how many days are
+* left in the year, taking leap years into account
+* @month: month in number format
+* @day: day of month
+* @year: year
+* Return: void
+*/
+
+void print_remaining_days(int month, int day, int year)
+{
+if ((year % 4 == 0 && !(year % 100 == 0)) || year % 400 == 0)
+{
+if (month > 2 && day >= 60)
+{
+day++;
+}
+
+printf("Day of the year: %d\n", day);
+printf("Remaining days: %d\n", 366 - day);
+}
+else
+{
+if (month == 2 && day == 60)
+{
+printf("Invalid date: %02d/%02d/%04d\n", month, day - 31, year);
+}
+else
+{
+printf("Day of the year: %d\n", day);
+printf("Remaining days: %d\n", 365 - day);
+}
+}
+}